1. Write a program that prompts for and reads a line of
text and uses a stack to reverse that line of text.
The program then shows each reversed line on the
screen. The program continues prompting, reading and
displaying until the user enters 'end' at the beginning
of the line input prompt.
2. Write a program to compress an ASCII text file and to
recover the original text from the compressed text.
Whether the program is compressing or uncompressing the
text will be indicated by a command line switch. The
switch **-c** will indicate that compression is to
take place. The switch **-u** will indicate that
uncompression is to take place. The text file will be
read by redirection of **stdin** on the command
line. The compressed text will be written to a file by
using redirection of **stdout** on the command line.
Compression squeezes a given amount of information so
that it requires less storage. We consider a bit
compression technique in which eight characters are
compressed into seven bytes, resulting in a 12.5%
saving in storage. This technique exploits the fact
that no ASCII letter or punctuation mark uses the
eighth bit of a byte. Therefore, the eighth bit of
each of the seven bytes can be used to sotre the eighth
character.
For example, the word **ziggurat** is represented in
eight bytes as
byte 0 0111 1010 z
byte 1 0110 1001 i
byte 2 0110 0111 g
byte 3 0110 0111 g
byte 4 0111 0101 u
byte 5 0111 0010 r
byte 6 0110 0001 a
byte 7 0111 0100 t
The seven significant bits of byte 0 can be distributed
into the seven unused positions of bytes 1 through 7.
The seven remaining bytes then appear as
byte 1 1 110 1001
byte 2 1 110 0111
byte 3 1 110 0111
byte 4 1 111 0101
byte 5 0 111 0010
byte 6 1 110 0001
byte 7 0 111 0100
3. Fill in the missing pieces where indicated.
#include
#include
#include
#include
#define MAX_N_A 80
#define MAX_SSN 11+1
struct EmpPayrollInfo
{
int hours;
int rate;
};
struct EmpPersonalInfo
{
char *name;
char *address;
char ssn[MAX_SSN+1];
int id;
EmpPayrollInfo *payroll;
};
int main()
{
char buffer[MAX_N_A+1];
int i, len;
EmpPersonalInfo *emp;
//
// allocate the space for the structure
//
emp = _______________// fill this ________________________
___________________// fill in what goes ______________
//
// prompt for the name and then store it in the
// structure
//
cout << "Enter employee's name: ";
fgets(buffer, MAX_N_A, stdin);
len = strlen(buffer);
//
// allocate space for the name
//
emp->name = _________________// fill this ________________
______________// fill in what goes ___________________
memset(emp->name, 0, len);
strncpy(emp->name, buffer, len-1);
//
// prompt for the address and then store it in the
// structure
//
______________________// fill in what goes _____________
//
// prompt for the ssn and store it in the structure
//
_____________________// fill in what goes ______________
//
// prompt for the emp id and store it in the structure
//
____________________// fill in what goes _______________
//
// prompt for some number of weeks of payroll data
//
cout << "How many weeks of payroll data? ";
cin >> len;
//
// note: this basically allocates an array of 'len'
// size
//
emp->payroll = ___________// fill in what goes here ________
_________________________// fill in what goes __________
//
// fill in the array
//
for (i=0; i<< "Enter hours for week " << i+1 << ": ";
__________________// fill in what goes ______________
cout << "Enter rate for week " << i+1 << ": ";
_________________// fill in what goes _______________
}
//
// print out all employee info
//
cout << ___________// fill in what goes ________________
//
// loop to print array held data
//
for (i=0; i<< __________// fill in what goes
_____________
}
}